4.9t^2+2.44-10=0

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Solution for 4.9t^2+2.44-10=0 equation:



4.9t^2+2.44-10=0
We add all the numbers together, and all the variables
4.9t^2-7.56=0
a = 4.9; b = 0; c = -7.56;
Δ = b2-4ac
Δ = 02-4·4.9·(-7.56)
Δ = 148.176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{148.176}}{2*4.9}=\frac{0-\sqrt{148.176}}{9.8} =-\frac{\sqrt{}}{9.8} $
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{148.176}}{2*4.9}=\frac{0+\sqrt{148.176}}{9.8} =\frac{\sqrt{}}{9.8} $

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